Misc:
Invest on Matrix
解锁hint1就知道是一个version2的二维码，剩下的就是不断解锁补全直到可以通过纠错识别出来，这是基础结构，我们优先补全右下角再逐渐保持中心完整，最后脚本如下：
from PIL import Image
import os
def make_matrix():
m = [[0]*25 for _ in range(25)]
def place_finder(r,c):
for i in range(7):
for j in range(7):
v = 1 if (i in (0,6) or j in (0,6) or (2<=i<=4 and 2<=j<=4)) else 0
m[r+i][c+j] = v
place_finder(0,0)
place_finder(0,18)
place_finder(18,0)
for j in range(25):
m[6][j] = 1 if j%2==0 else 0
for i in range(25):
m[i][6] = 1 if i%2==0 else 0
for i in range(5):
for j in range(5):
r = 16+i
c = 16+j
v = 1 if (i in (0,4) or j in (0,4) or (i==2 and j==2)) else 0
m[r][c] = v
return m
def apply_block(m, k, vals):
r = (k-1)//5
c = (k-1)%5
sr = r*5
sc = c*5
for idx, v in enumerate(vals):
dr = idx//5
dc = idx%5
m[sr+dr][sc+dc] = v
def save_png(m, path, cell_size=12, border=4):
n = len(m)
s = (n + 2*border) * cell_size
img = Image.new('RGB', (s, s), 'white')
px = img.load()
for y in range(n):
for x in range(n):
col = (0,0,0) if m[y][x]==1 else (255,255,255)
for dy in range(cell_size):
for dx in range(cell_size):
px[(x+border)*cell_size+dx, (y+border)*cell_size+dy] = col
img.save(path)
print(path)
def main():
m = make_matrix()
b2 = [1,1,0,1,1,0,1,0,1,1,0,1,0,1,0,0,1,0,0,0,0,1,0,0,1]
b6 = [1,0,0,0,0,1,1,1,1,1,0,0,0,0,0,0,0,1,1,1,1,0,1,0,0]
b7 = [0,1,0,1,0,1,1,0,1,0,0,0,0,1,0,0,1,0,1,0,1,0,1,0,1]
b8 = [0,0,1,1,0,1,0,1,0,1,0,1,1,1,1,0,0,1,0,0,0,1,0,0,1]
b9 = [1,0,0,1,0,0,1,0,1,1,0,0,0,0,0,1,1,1,1,1,1,1,0,1,0]
b10 = [0,0,0,0,1,1,1,1,1,1,0,0,0,0,0,0,0,1,1,1,0,1,0,1,1]
b11 = [1,1,0,1,1,1,1,1,0,1,0,1,1,0,0,1,0,0,0,1,1,0,0,1,1]
b13 = [1,1,0,1,0,0,0,1,0,1,1,1,1,1,0,1,1,0,1,1,1,0,0,1,0]
b14 = [1,1,1,0,1,0,0,0,0,1,1,0,1,0,1,1,1,0,1,0,0,0,0,1,0]
b18 = [1,1,1,0,1,0,0,1,1,1,1,0,0,0,1,1,1,0,0,1,0,1,1,1,1]
b19 = [0,1,1,1,1,0,1,1,1,1,0,1,0,0,0,1,1,0,1,0,1,1,0,0,0]
b15 = [1,1,1,1,1,1,0,0,0,1,1,0,0,0,1,0,0,0,1,0,0,1,0,0,1]
b20 = [0,0,0,1,0,1,1,0,1,1,1,1,1,1,1,1,1,0,1,1,1,0,0,1,1]
b21 = [1,0,1,1,1,1,0,1,1,1,1,0,1,1,1,1,0,0,0,0,1,1,1,1,1]
b16 = [1,0,1,0,1,1,0,1,0,1,0,0,0,0,0,1,1,1,1,1,1,0,0,0,0]
b12 = [1,1,0,1,1,0,0,1,1,0,1,1,0,1,0,0,0,0,0,1,1,1,1,1,0]
b24 = [1,1,1,1,1,0,0,0,1,1,1,0,1,1,1,1,0,1,0,1,0,1,0,0,0]
b25 = [1,0,0,0,0,0,0,1,0,1,0,0,1,0,1,0,1,0,0,1,0,0,1,1,1]
apply_block(m, 2, b2)
apply_block(m, 6, b6)
apply_block(m, 7, b7)
apply_block(m, 8, b8)
apply_block(m, 9, b9)
apply_block(m, 10, b10)
apply_block(m, 11, b11)
apply_block(m, 13, b13)
apply_block(m, 14, b14)
apply_block(m, 12, b12)
apply_block(m, 18, b18)
apply_block(m, 19, b19)
apply_block(m, 15, b15)
apply_block(m, 20, b20)
apply_block(m, 21, b21)
apply_block(m, 16, b16)
apply_block(m, 24, b24)
apply_block(m, 25, b25)
out = os.path.abspath(os.path.join(os.path.dirname(__file__), "qr_recon.png"))
save_png(m, out)
if __name__ == "__main__":
main()
得到flag。
